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# a pretty straightforward Muenchian grouping test
from Xml.Xslt import test_harness
sheet_1 = """<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" indent="yes"/>
<xsl:key name="skills-by-mark" match="skill" use="@mark"/>
<xsl:template match="skills">
<table>
<!-- process a set consisting of the first skill element for each mark -->
<xsl:for-each select="skill[count(.|key('skills-by-mark',@mark)[1])=1]">
<tr>
<td><b><xsl:value-of select="concat(@mark,' skills:')"/></b></td>
<td>
<!-- process all skill elements having the current skill's mark -->
<xsl:for-each select="key('skills-by-mark',@mark)">
<xsl:value-of select="@name"/>
<xsl:if test="position()!=last()"><br/></xsl:if>
</xsl:for-each>
</td>
</tr>
</xsl:for-each>
</table>
</xsl:template>
</xsl:stylesheet>"""
source_1 = """<skills>
<skill mark="excellent" name="excellentskill"/>
<skill mark="excellent" name="excellent skill"/>
<skill mark="good" name="goodskill"/>
<skill mark="good" name="goodskill"/>
<skill mark="basic" name="basicskill"/>
<skill mark="basic" name="basicskill"/>
<skill mark="excellent" name="excellentskill"/>
<skill mark="good" name="goodskill"/>
<skill mark="basic" name="basicskill"/>
</skills>"""
expected_1 = """<table>
<tr>
<td><b>excellent skills:</b></td>
<td>excellentskill
<br>excellent skill
<br>excellentskill
</td>
</tr>
<tr>
<td><b>good skills:</b></td>
<td>goodskill
<br>goodskill
<br>goodskill
</td>
</tr>
<tr>
<td><b>basic skills:</b></td>
<td>basicskill
<br>basicskill
<br>basicskill
</td>
</tr>
</table>"""
def Test(tester):
source = test_harness.FileInfo(string=source_1)
sheet = test_harness.FileInfo(string=sheet_1)
test_harness.XsltTest(tester, source, [sheet], expected_1,
title='ordinary Muenchian grouping with keys')
return
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